(x^2+2x-3)(4x-5)=0

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Solution for (x^2+2x-3)(4x-5)=0 equation: 


Simplifying
(x2 + 2x + -3)(4x + -5) = 0

Reorder the terms:
(-3 + 2x + x2)(4x + -5) = 0

Reorder the terms:
(-3 + 2x + x2)(-5 + 4x) = 0

Multiply (-3 + 2x + x2) * (-5 + 4x)
(-3(-5 + 4x) + 2x * (-5 + 4x) + x2(-5 + 4x)) = 0
((-5 * -3 + 4x * -3) + 2x * (-5 + 4x) + x2(-5 + 4x)) = 0
((15 + -12x) + 2x * (-5 + 4x) + x2(-5 + 4x)) = 0
(15 + -12x + (-5 * 2x + 4x * 2x) + x2(-5 + 4x)) = 0
(15 + -12x + (-10x + 8x2) + x2(-5 + 4x)) = 0
(15 + -12x + -10x + 8x2 + (-5 * x2 + 4x * x2)) = 0
(15 + -12x + -10x + 8x2 + (-5x2 + 4x3)) = 0

Combine like terms: -12x + -10x = -22x
(15 + -22x + 8x2 + -5x2 + 4x3) = 0

Combine like terms: 8x2 + -5x2 = 3x2
(15 + -22x + 3x2 + 4x3) = 0

Solving
15 + -22x + 3x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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